The Schwarz–Pick Lemma: Holomorphic Maps Contract the Disk
Let be the open unit disk. Suppose is holomorphic (not necessarily a bijection).
Prove that for any two points ,
In other words, does not increase the pseudo-hyperbolic distance on .
Bonus insight: When does equality hold?
Answer: Schwarz–Pick Lemma: Holomorphic Maps Contract the Disk
Key Idea / Intuition
The pseudo-hyperbolic distance is precisely the quantity that Möbius automorphisms of preserve. The strategy is: conjugate by two Möbius maps so that the resulting function fixes the origin, then apply the Schwarz Lemma (which says a holomorphic self-map of fixing contracts distances from the origin). The inequality pops out automatically.
Formal Proof / Solution
Step 1: Recall the Möbius automorphisms of .
For any , define the automorphism
This is a biholomorphism with , and .
Step 2: Reduce to the Schwarz Lemma.
Fix and define
This is a holomorphic map from to (since and ), and
Step 3: Apply the Schwarz Lemma.
Since is holomorphic with , the Schwarz Lemma gives
Step 4: Unwind the conjugation.
Set (so ). Then
The Schwarz bound becomes
which is exactly
Equality case.
Equality for some forces (by the equality case of the Schwarz Lemma) that for some , i.e., is a rotation. Unwinding, itself must be a Möbius automorphism of . Thus:
Equality holds (for some ) if and only if is a biholomorphic automorphism of — i.e., for some and .
Geometric punchline. The Schwarz–Pick Lemma says that equipped with the Poincaré (hyperbolic) metric has the property that every holomorphic self-map is a contraction (isometry iff it's an automorphism). This is a cornerstone of hyperbolic geometry and complex dynamics.
Source: Stein & Shakarchi, Complex Analysis, Chapter 8; classical folklore