🧮 Brain Teaser

The Schwarz–Pick Lemma: Holomorphic Maps Contract the Disk

Let D={zC:z<1}\mathbb{D} = \{z \in \mathbb{C} : |z| < 1\} be the open unit disk. Suppose f:DDf : \mathbb{D} \to \mathbb{D} is holomorphic (not necessarily a bijection).

Prove that for any two points z,wDz, w \in \mathbb{D},

f(z)f(w)1f(w)f(z)zw1wˉz.\left| \frac{f(z) - f(w)}{1 - \overline{f(w)}\, f(z)} \right| \leq \left| \frac{z - w}{1 - \bar{w}\, z} \right|.

In other words, ff does not increase the pseudo-hyperbolic distance on D\mathbb{D}.

Bonus insight: When does equality hold?

Schwarz LemmaMöbius transformationshyperbolic geometryholomorphic mapsunit disk

Answer: Schwarz–Pick Lemma: Holomorphic Maps Contract the Disk

Key Idea / Intuition

The pseudo-hyperbolic distance ρ(z,w)=zw1wˉz\rho(z, w) = \left|\frac{z-w}{1-\bar{w}z}\right| is precisely the quantity that Möbius automorphisms of D\mathbb{D} preserve. The strategy is: conjugate ff by two Möbius maps so that the resulting function fixes the origin, then apply the Schwarz Lemma (which says a holomorphic self-map of D\mathbb{D} fixing 00 contracts distances from the origin). The inequality pops out automatically.


Formal Proof / Solution

Step 1: Recall the Möbius automorphisms of D\mathbb{D}.

For any aDa \in \mathbb{D}, define the automorphism

φa(z)=za1aˉz.\varphi_a(z) = \frac{z - a}{1 - \bar{a}\, z}.

This is a biholomorphism DD\mathbb{D} \to \mathbb{D} with φa(a)=0\varphi_a(a) = 0, and φaφa=id\varphi_a \circ \varphi_a = \mathrm{id}.

Step 2: Reduce to the Schwarz Lemma.

Fix wDw \in \mathbb{D} and define

g=φf(w)fφw:DD.g = \varphi_{f(w)} \circ f \circ \varphi_w : \mathbb{D} \to \mathbb{D}.

This is a holomorphic map from D\mathbb{D} to D\mathbb{D} (since f:DDf : \mathbb{D} \to \mathbb{D} and φf(w):DD\varphi_{f(w)} : \mathbb{D} \to \mathbb{D}), and

g(0)=φf(w)(f(φw(0)))=φf(w)(f(w))=0.g(0) = \varphi_{f(w)}(f(\varphi_w(0))) = \varphi_{f(w)}(f(w)) = 0.

Step 3: Apply the Schwarz Lemma.

Since g:DDg : \mathbb{D} \to \mathbb{D} is holomorphic with g(0)=0g(0) = 0, the Schwarz Lemma gives

g(ζ)ζfor all ζD.|g(\zeta)| \leq |\zeta| \quad \text{for all } \zeta \in \mathbb{D}.

Step 4: Unwind the conjugation.

Set ζ=φw(z)\zeta = \varphi_w(z) (so z=φw(ζ)z = \varphi_w(\zeta)). Then

g(ζ)=φf(w)(f(z)).g(\zeta) = \varphi_{f(w)}(f(z)).

The Schwarz bound becomes

φf(w)(f(z))φw(z),|\varphi_{f(w)}(f(z))| \leq |\varphi_w(z)|,

which is exactly

f(z)f(w)1f(w)f(z)zw1wˉz.\left| \frac{f(z) - f(w)}{1 - \overline{f(w)}\, f(z)} \right| \leq \left| \frac{z - w}{1 - \bar{w}\, z} \right|. \qquad \blacksquare


Equality case.

Equality g(ζ)=ζ|g(\zeta)| = |\zeta| for some ζ0\zeta \neq 0 forces (by the equality case of the Schwarz Lemma) that g(ζ)=eiθζg(\zeta) = e^{i\theta}\zeta for some θR\theta \in \mathbb{R}, i.e., gg is a rotation. Unwinding, ff itself must be a Möbius automorphism of D\mathbb{D}. Thus:

Equality holds (for some zwz \neq w) if and only if ff is a biholomorphic automorphism of D\mathbb{D} — i.e., f(z)=eiθφa(z)f(z) = e^{i\theta} \varphi_a(z) for some aDa \in \mathbb{D} and θR\theta \in \mathbb{R}.


Geometric punchline. The Schwarz–Pick Lemma says that D\mathbb{D} equipped with the Poincaré (hyperbolic) metric ds=2dz1z2ds = \frac{2|dz|}{1-|z|^2} has the property that every holomorphic self-map is a contraction (isometry iff it's an automorphism). This is a cornerstone of hyperbolic geometry and complex dynamics.

Source: Stein & Shakarchi, Complex Analysis, Chapter 8; classical folklore

Type: Complex AnalysisSource: Stein & Shakarchi, Complex Analysis, Chapter 8; classical folkloreEdit on GitHub ↗